Math Algebra
posted by Kayleigh .
i'm having troubles with some sums
how would you factorize completely
9a(squared)  b(squared)?
or an expression like
27x(squared)  1/3y(squared)
its difficult. have many more.

9a^2  b^2
= (3a)^2 (b)^2
= (3a+b)(3ab)
i couldn't understand the second one though. Hope it helps!!! :) 
whenever you have the difference of two squares
the factors are the sum and the difference of the two that are squared.
a^2b^2 ( a + b )( a  b ) 
27x(squared)  1/3y(squared)
first take (1/3) out
(1/3) (3^4 x^2  y^2)
(1/3)(3^2 + y)(3^2  y)
(1/3)(9+y)(9y) 
1/3) (3^4 x^2  y^2)
(1/3)(3^2 x + y)(3^2  y)
(1/3)(9x+y)(9xy)