Posted by Kayleigh on Sunday, January 4, 2009 at 4:46pm.
9a^2 - b^2
= (3a)^2- (b)^2
= (3a+b)(3a-b)
i couldn't understand the second one though. Hope it helps!!! :-)
whenever you have the difference of two squares
the factors are the sum and the difference of the two that are squared.
a^2-b^2 ( a + b )( a - b )
27x(squared) - 1/3y(squared)
first take (1/3) out
(1/3) (3^4 x^2 - y^2)
(1/3)(3^2 + y)(3^2 - y)
(1/3)(9+y)(9-y)
1/3) (3^4 x^2 - y^2)
(1/3)(3^2 x + y)(3^2 - y)
(1/3)(9x+y)(9x-y)
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