find thedomain and range of {(7,-2), (-6,-4) (9-9,)-(5-5)}=
evaluate f(x) +3x^2-4x-3at f(x-1)=
evaluate f(x)= -5x+8 atf(-3)=
it will be well appreciated of what how and help with these math problems plz thank you
I answered the domain and range one above
f(x-1) = 3(x-1)^2 - 4 (x-1) - 3
= 3 x^2 -6 x + 3 - 4x + 4 - 3
= 3 x^2 - 10 x +4
f(-3) = 15 + 8 = 23
Sure! Let's go through each problem step by step:
1. Finding the domain and range of a set of points:
The domain of a function is the set of all possible x-values, and the range is the set of all possible y-values. To find the domain and range of the given set of points, we examine the x and y values in the set.
The given set of points is {(7,-2), (-6,-4), (9,-9), (5,-5)}.
For the domain, we look at all the x-values: 7, -6, 9, and 5. The domain is the set of all these x-values, which is {7, -6, 9, 5}.
For the range, we look at all the y-values: -2, -4, -9, and -5. The range is the set of all these y-values, which is {-2, -4, -9, -5}.
Therefore, the domain is {7, -6, 9, 5} and the range is {-2, -4, -9, -5}.
2. Evaluating a function at a given value:
To evaluate a function at a specific value, substitute the given value into the function.
The function f(x) = 3x^2 - 4x - 3 is given. Let's evaluate it at f(x-1).
To do this, we substitute x-1 for x in the function: f(x-1) = 3(x-1)^2 - 4(x-1) - 3.
Now simplify the expression: f(x-1) = 3(x^2 - 2x + 1) - 4x + 4 - 3.
Further simplifying: f(x-1) = 3x^2 - 6x + 3 - 4x + 4 - 3.
Combining like terms: f(x-1) = 3x^2 - 10x + 4.
So, f(x-1) = 3x^2 - 10x + 4.
3. Evaluating a function at a specific value:
To evaluate a function at a specific value, substitute the given value into the function.
The function f(x) = -5x + 8 is given. Let's evaluate it at f(-3).
To do this, substitute -3 for x in the function: f(-3) = -5(-3) + 8.
Simplifying, f(-3) = 15 + 8.
Therefore, f(-3) = 23.
I hope this helps! Let me know if you have any further questions.