A set of input values is sometimes referred to as the replacement set for the independent variables. Evaluate each function for the given replacement set.
f(x)=3x-6;{-3.5,-1,1/4,2,11}
f(x)=x(1-2x);{-8,2/3,1,9,4}
It looks to me like they just want you to calculate a given function f(x) at set of x values. You will end up with a set of f(x) values. Then they want you do it again for a different set of independent valiables with a different
f(x)
For example, if f(x) = 3x -6 and x = 2, then f(x) = 0
If f(x) = x(1-2x) and x = 1, then f(x) = -1
In my opinion, someone is trying to make algebra more confusing than it really is, by talking about "replacement sets". Fads like this come and go.
A set of input values is sometimes referred to as the replacement set for the independent variables. Evaluate each function for the given replacement set.
f(x)=3x-6;{-3.5,-1,1/4,2,11}
i agree and drwls is right.and person is right they teach us and show is harder and confussing than is.
All of that complicated talk means:
Use each of those numbers for x
To evaluate each function for the given replacement set, you need to substitute the input values from the replacement set into the given functions and compute the corresponding outputs.
For f(x)=3x-6;{-3.5,-1,1/4,2,11}:
1. Substitute -3.5 into the function: f(-3.5) = 3(-3.5) - 6 = -10.5 - 6 = -16.5.
2. Substitute -1 into the function: f(-1) = 3(-1) - 6 = -3 - 6 = -9.
3. Substitute 1/4 into the function: f(1/4) = 3(1/4) - 6 = 3/4 - 6 = -5.25.
4. Substitute 2 into the function: f(2) = 3(2) - 6 = 6 - 6 = 0.
5. Substitute 11 into the function: f(11) = 3(11) - 6 = 33 - 6 = 27.
The outputs for the given replacement set are {-16.5, -9, -5.25, 0, 27}.
For f(x)=x(1-2x);{-8,2/3,1,9,4}:
1. Substitute -8 into the function: f(-8) = -8(1 - 2(-8)) = -8(1 + 16) = -8(17) = -136.
2. Substitute 2/3 into the function: f(2/3) = (2/3)(1 - 2(2/3)) = (2/3)(1 - 4/3) = (2/3)(-1/3) = -2/9.
3. Substitute 1 into the function: f(1) = 1(1 - 2(1)) = 1(1 - 2) = 1(-1) = -1.
4. Substitute 9 into the function: f(9) = 9(1 - 2(9)) = 9(1 - 18) = 9(-17) = -153.
5. Substitute 4 into the function: f(4) = 4(1 - 2(4)) = 4(1 - 8) = 4(-7) = -28.
The outputs for the given replacement set are {-136, -2/9, -1, -153, -28}.