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April 18, 2014

April 18, 2014

Posted by **Kate** on Sunday, January 4, 2009 at 12:09am.

f(x)=3x-6;{-3.5,-1,1/4,2,11}

f(x)=x(1-2x);{-8,2/3,1,9,4}

- algebra II -
**drwls**, Sunday, January 4, 2009 at 12:19amIt looks to me like they just want you to calculate a given function f(x) at set of x values. You will end up with a set of f(x) values. Then they want you do it again for a different set of independent valiables with a different

f(x)

For example, if f(x) = 3x -6 and x = 2, then f(x) = 0

If f(x) = x(1-2x) and x = 1, then f(x) = -1

In my opinion, someone is trying to make algebra more confusing than it really is, by talking about "replacement sets". Fads like this come and go.

- algebra II -
**Kate**, Sunday, January 4, 2009 at 12:41amA set of input values is sometimes referred to as the replacement set for the independent variables. Evaluate each function for the given replacement set.

f(x)=3x-6;{-3.5,-1,1/4,2,11}

- algebra II -
**sherri**, Sunday, January 4, 2009 at 12:56ami agree and drwls is right.and person is right they teach us and show is harder and confussing than is.

- algebra II -
**Damon**, Sunday, January 4, 2009 at 3:31amAll of that complicated talk means:

Use each of those numbers for x

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