Posted by **Mark** on Saturday, January 3, 2009 at 7:38pm.

Im doing my homework and it provides barely any info. here is the question.

Mr Harrison has a very large backyard. He contacted the Clover Pool Company to have a pool installed in the shape of a rectangle. The Clover Pool Company would build a pool that has a perimeter of 72 yards. Mr. Harrison would be allowed to choose the dimensions (length and width) of the pool.He chose the dimensions that would give him a greatest area possible. What are the dimensions of the pool that would give Mr. the greatest area?

- math -
**drwls**, Saturday, January 3, 2009 at 7:49pm
If L is the length and W is the width,

2(L+W) = 72

L+W = 36

W = 36 -L

Area = L(36 -L)= 36L- L^2

Set dA/dL = 0 = 0 and solve for L, if you know calculus. If you don't, rewrite the above equation as

Area = 18^2 - (L-18)^2

This is a maximum when the (L-18) term is zero, so L = 18.

- math -
**Mark**, Saturday, January 3, 2009 at 8:01pm
thanks dude you rock

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