Posted by **Barbara** on Saturday, January 3, 2009 at 4:30pm.

The position of two particles on the s-axis are s1= cos(t) and s2= cos(t+(symbol for pie)/4)

a. what is the farthest apart the particles ever get?

b. when do the particles collide?

- calculus -
**bobpursley**, Saturday, January 3, 2009 at 4:31pm
I think it would be of more benefit if you posted your thinking or work, and we critiqued it.

- calculus -
**Barbara**, Saturday, January 3, 2009 at 4:36pm
Well I am in AP Calculus and I don't understand the class to well.

- calculus -
**Damon**, Saturday, January 3, 2009 at 4:56pm
difference = y = cos ( t + pi/4) - cos t

for part a

take dy/dt and set to 0

dy/dt = -sin (t+pi/4) + sin t

0 = sin t - sin (t+pi/4)

sin t = sin (t+pi/4)

sin (a+b) =sin a cos b + cos a sin b

so

sin t = sin t cos pi/4 + cos t sin pi/4

sin t = sin t /sqrt 2 + cos t/sqrt 2

sqrt 2 sin t = sin t + cos t

(sqrt 2-1) = cos t/sin t = cot t

cot t = .4142

t = 67.5 degrees = 1.178 radians

also in other quadrants where cot t =.4142

NOW, go back and find y

for part b,just find when cos (t+pi/4) = cos t

- calculus -
**Barbara**, Saturday, January 3, 2009 at 5:04pm
Thank You

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