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March 5, 2015

March 5, 2015

Posted by **Lucy** on Saturday, January 3, 2009 at 4:06pm.

My work: (red cube = [1,2,3,4]

white cube = [4,3,2,1]

Probability of a 2 on the red cube is 1/4. Is this correct?

- Pre-Cal -
**Damon**, Saturday, January 3, 2009 at 4:24pmBlock the whole matrix out with read along the top and white down

write all the sums in the boxes of the matrix, which contains 36 numbers.

Of those 36,

4+3+2+1 = 10

have sums less than or equal to 5

Of those 10, 3 show the number 2 on red

w1-r2 , w2-r2 , w3-r2

so 3/10

- Pre-Cal -
**bobpursley**, Saturday, January 3, 2009 at 4:24pmIf the sum is five, then red,white can be

1,4

2,3

3,2

4,1

if the sum is four, then

1,3

2,2

3,1

if the sum is three, then

1,2

2,1

if the sum is two, then

1,1

I see 10 possible combinations, and the red is 2 in 3 of them.

Pr(red=2, sum is =<5) is 3/10

- Pre-Cal -
**drwls**, Saturday, January 3, 2009 at 4:31pmIf the sum of the two cubes is 2, 3, 4, or 5 (all the possibilities that are allowed), then the red cube can only be 1, 2, 3 or 4.

The possibile combinations are:

W R

1 4

1 3

1 2

1 1

2 3

2 2

2 1

3 2

3 1

4 1

There are three combinations with a red 2 out of ten allowed. That makes the probability 3/10

- Pre-Cal -
**Damon**, Saturday, January 3, 2009 at 5:28pmLOL - tomorrow we do Blackjack :)

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