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November 23, 2014

November 23, 2014

Posted by **Patrick** on Saturday, January 3, 2009 at 1:05pm.

Scenario: Suppose that the width of a rectangle is 5 inches shorter than the length, and that the perimeter of the rectangle is 50.

Question: Set up an equation for the perimeter involving only L, the length of the rectangle.

Answer: I came up with....

5L + 5(L-5) = 50

Is this correct?

- Algebra -
**Damon**, Saturday, January 3, 2009 at 1:12pmdimensions are L and L-5

perimeter = 2 L + 2 (L-5) = 50

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