I think I have the correct equation, but can someone please double check and tell me if I am correct.
Scenario: Suppose that the width of a rectangle is 5 inches shorter than the length, and that the perimeter of the rectangle is 50.
Question: Set up an equation for the perimeter involving only L, the length of the rectangle.
Answer: I came up with....
5L + 5(L-5) = 50
Is this correct?
Algebra - Damon, Saturday, January 3, 2009 at 1:12pm
dimensions are L and L-5
perimeter = 2 L + 2 (L-5) = 50