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July 31, 2014

July 31, 2014

Posted by **Dala** on Friday, January 2, 2009 at 9:59pm.

- Physics -
**bobpursley**, Friday, January 2, 2009 at 10:02pmThe sum of the distances is 88m.

They collide at time t.

d=1/2 .300*t^2

88-d=1/2 .200 t^2

divide the second equation by the first will lead to this

88-d=d(2/3) solve for d

- Physics -
**Dala**, Friday, January 2, 2009 at 10:08pmthanks

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