Physics
posted by Dala .
Two knights on horseback start from rest 88.0 m apart and ride directly toward each other to do battle. Sir George's acceleration has a magnitude of .300 m/s^2, while Sir Alfred's has a magnitude of .200 m/s^2. Relative to sir Ggeorge's starting point, where do the knights collide?

The sum of the distances is 88m.
They collide at time t.
d=1/2 .300*t^2
88d=1/2 .200 t^2
divide the second equation by the first will lead to this
88d=d(2/3) solve for d 
thanks