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July 22, 2014

July 22, 2014

Posted by **lyne** on Friday, January 2, 2009 at 7:52pm.

Answer in J/gram degree celcius

how do i set this problem up? I already sorted the information.

- chemistry HELP -
**DrBob222**, Friday, January 2, 2009 at 8:37pm[mass Cu x specific heat Cu x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0

Solve for specific heat Cu. It's easier to put in all the numbers first into the above, do the math, then solve for specific heat Cu last. Post your work if you get stuck. For your information, note the correct spelling of Celsius.

- chemistry HELP -
**GK**, Friday, January 2, 2009 at 8:41pmheat = (sp. heat)(grams)(temp. change)

or q = (C)(m)(Tf-Ti)

Heat released by Cu = Heat absorbed by H2O

(C)(46.2g)(95.4C-21.8C)= (4.18J/g.C)(75.0g)(21.8C-19.6C)

Solve for C to get the specific heat of copper.

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