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October 22, 2014

October 22, 2014

Posted by **???E** on Thursday, January 1, 2009 at 11:37pm.

- algebra -
**Reiny**, Thursday, January 1, 2009 at 11:51pm<<...the width of the rectangle is 6 cm than the side of the square>

6 cm**more**or 6 cm**less**

I am going to assume it is "less"

so we would have

(2x-4)(x-6) = x^2

Solve for x and take it from there

if it is "more" then

(2x-4)(x+6) = x^2 and solve

- algebra -
**DrBob222**, Thursday, January 1, 2009 at 11:53pmCheck my thinking on this.

S = side of the square.

L= length of rectangle.

W = width of rectangle.

4S = perimeter of square

2L + 2W = perimeter of rectangle.

=========================

perimeter is the same; therefore,

4S = 2L + 2W

2S = L + 4

S = W+6

Solve for S, L, W and calculate perimeter. I tried this and have S = 10, L = 16

W = 4

All of the units are cm.

Perimeter is 40 cm.

- algebra -
**???E**, Thursday, January 1, 2009 at 11:57pmthank u

- algebra -
**Reiny**, Friday, January 2, 2009 at 12:03amscrap my solution, I misread the question.

go with DrBob's method.

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