<<...the width of the rectangle is 6 cm than the side of the square>
6 cm more or 6 cm less
I am going to assume it is "less"
so we would have
(2x-4)(x-6) = x^2
Solve for x and take it from there
if it is "more" then
(2x-4)(x+6) = x^2 and solve
Check my thinking on this.
S = side of the square.
L= length of rectangle.
W = width of rectangle.
4S = perimeter of square
2L + 2W = perimeter of rectangle.
perimeter is the same; therefore,
4S = 2L + 2W
2S = L + 4
S = W+6
Solve for S, L, W and calculate perimeter. I tried this and have S = 10, L = 16
W = 4
All of the units are cm.
Perimeter is 40 cm.
scrap my solution, I misread the question.
go with DrBob's method.
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