I'm a little confused on how to solve this system of equations.
5a=5
6b-3c=15
2a+7c=-5
Thanks
The first equation gives a = 1 when you divide both sides by 5
Now do the third equation substituting 1 for a
2*1 + 7 c = -5
7 c = -7
c = -1
so now we have a = 1 and c = -1
Use those in the middle equation
6 b - 3 (-1) = 15
6 b + 3 = 15
6 b = 12
b = 2
Ah, I get it now. Thanks
To solve the system of equations:
1. Start by isolating one variable in each equation. Let's start with the first equation:
5a = 5
Divide both sides of the equation by 5 to isolate "a":
a = 1
2. Now let's work on the second equation:
6b - 3c = 15
Add 3c to both sides to move the term involving "c" to the other side of the equation:
6b = 3c + 15
3. Finally, let's focus on the third equation:
2a + 7c = -5
4. Now substitute the value of "a" from equation 1 into equation 3:
2(1) + 7c = -5
Simplify the equation:
2 + 7c = -5
Subtract 2 from both sides to isolate "c":
7c = -7
5. Divide both sides of the equation by 7, so "c" is isolated:
c = -1
6. Now substitute the values of "a" and "c" into equation 2:
6b - 3(-1) = 15
Simplify the equation:
6b + 3 = 15
Subtract 3 from both sides to isolate "b":
6b = 12
Divide both sides of the equation by 6, so "b" is isolated:
b = 2
Therefore, the solution to the system of equations is:
a = 1, b = 2, and c = -1.