Posted by **sherry** on Wednesday, December 31, 2008 at 4:52am.

Find the limit of the function:

(tanp)(x-1)/(tanq)(x-1)

as x approaches 1. We're hinted at using the result that sinx/x = 1 as x approaches 0.

Im not sure how we go abt doing this qs.

thanks in advance

- do not understand question -
**Damon**, Wednesday, December 31, 2008 at 5:25am
as written the answer is simply tanp/tanq

what is tanp?

what is tanq ?

what is p and what is q ?

Does this mean tan (px - p) / tan (qx - q)? or something?

- math -
**sherry**, Wednesday, December 31, 2008 at 6:51am
tanp and tanq is short for tangent p and tangent q respectively(we havent been told where p is a variable or constant; same goes for q)

no it doesnt mean tan (px - p)

it wud be xtanp -tanp if u were to multiply it thru ..same for denominator

and the answer given is p/q

- math -
**bobpursley**, Wednesday, December 31, 2008 at 10:47am
(xtanp-tanP)/(xtanq-tanq) as x approachtes zero.

Unless p,q are somehow related to x, it is not equal to p/q.

- math -
**Reiny**, Wednesday, December 31, 2008 at 1:12pm
to get p/q, it looks like somebody canceled the "tan"

reminded me of the time when one of my students gave this solution to

Lim (sinx)/x as x = 0

= sin

I told him to sin no more, but he didn't get it.

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