factor the expression
2x^2+x-15
This one also factors.
I gave you the previous one, why don't you try this, the factors are quite simple.
Let me know what you got.
Reiny i got
(x+5)(x-3)
x=-5 or x=3
Not quite. You have to get +2x^2
(2x-5)(x+3) ought to do it.
not quite,
did you notice that the first term was 2x^2, so one of the factors must have started with 2x
so it had to be (2x...)(x....)
YOu should have expanded your answer to see if you get the original question back.
I got (2x-5(x+3)= 0
then
x = 5/2 or x = -3
To factor the expression 2x^2 + x - 15, we need to find two numbers whose product is equal to the product of the coefficient of the x^2 term (2) and the constant term (-15) and whose sum is equal to the coefficient of the x term (1).
Let's look for two numbers, a and b, such that a * b = 2 * (-15) = -30 and a + b = 1.
Now, we need to find two numbers that satisfy these conditions. By trying different pairs of numbers, we find that 6 and -5 fulfill these conditions since 6 * (-5) = -30 and 6 + (-5) = 1.
Next, we rewrite the expression using these pairs of numbers:
2x^2 + x - 15
= 2x^2 + 6x - 5x - 15
Now, we group the terms:
= (2x^2 + 6x) + (-5x - 15)
We can factor out a common factor from each group:
= 2x(x + 3) - 5(x + 3)
Notice that both terms now have a common factor of (x + 3). We can factor this out:
= (2x - 5)(x + 3)
Therefore, the factored form of the expression 2x^2 + x - 15 is (2x - 5)(x + 3).