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July 31, 2014

July 31, 2014

Posted by **Pam** on Friday, December 19, 2008 at 12:28pm.

- Math -
**Damon**, Friday, December 19, 2008 at 1:13pmtriangle A B F

North to AB = 70

North to AF = 25

so

angle FAB = 70-25 = 45

North to BF = 345 clockwise so 15 counterclockwise

so exterior angle AB to BF = 70 +15 = 85

so

angle ABF = 180 -85 = 95

that leaves angle AFB = 180 -45-95 = 40

then

sin 40/20.5 = sin 95/af = sin 45/bf

- Math -
**Pam**, Friday, December 19, 2008 at 2:27pmohh thanks

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