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August 1, 2014

August 1, 2014

Posted by **al** on Friday, December 19, 2008 at 1:50am.

solve. 2sin^(2)x=2+cosx

- pre-cal -
**Damon**, Friday, December 19, 2008 at 3:12am2 (1-cos^2 x) = 2 + cos x

2 - 2 cos^2 x = 2 + cos x

cos x + 2 cos^2 x = 0

cos x ( 1 + 2 cos x) = 0

cos x = 0 ---> x = 90 degrees (pi/2 radians etc)

cos x = -1/2 ---> x = 120 degrees, 240 degrees etc

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