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December 22, 2014

December 22, 2014

Posted by **Theresa** on Friday, December 19, 2008 at 12:20am.

Is it no value of c in that interval because the function is not continuous on that interval???

- calculus -
**Damon**, Friday, December 19, 2008 at 3:21amIt is continuous between -1 and +3. The blow up is at x = 3.

y = 6/(x-3)

dy/dx = -6/(x-3)^2

now slope from -1 to +2

y(-1) = 6/-4 = -3/2

y(2) = 6/-1 = -6

delta x = 2+1 = 3

so mean slope = (-6 + 3/2)/3 = -2 + 1/2 = -1.5

now where does derivative = -1.5 ?

-3/2 = -6/(x-3)^2

(x-3)^2 = 4

x-3 = +/- 2

x = 5 or x = 1

only x = 1 is on the interval from -1 to 2

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