Posted by Theresa on Thursday, December 18, 2008 at 11:58pm.
the only place where your function f(x) = 6/(x-3) is not continuous is at x= 3
your interval does not reach that value, so recall your definition of the Mean Value Theorem.
A series of YouTube clips that are done by Sal Khan offer really simple explanations.
Here is the one that deals with this topic.
http://www.youtube.com/watch?v=bGNMXfaNR5Q
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