Posted by **Theresa** on Thursday, December 18, 2008 at 11:58pm.

Find the values of c that satisfy the Mean Value Theorem for f(x)=6/x-3 on the interval [-1,2].

Is it no value of c in that interval because the function is not continuous on that interval???

- calculus -
**Reiny**, Friday, December 19, 2008 at 12:04am
the only place where your function f(x) = 6/(x-3) is not continuous is at x= 3

your interval does not reach that value, so recall your definition of the Mean Value Theorem.

A series of YouTube clips that are done by Sal Khan offer really simple explanations.

Here is the one that deals with this topic.

http://www.youtube.com/watch?v=bGNMXfaNR5Q

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