Posted by joe on Thursday, December 18, 2008 at 12:22am.
the first 3 are correct
for d)
the odds are 1,3,5,7,9,11,13
multiples of 3 are 3,6,9,12
now the numbers which are either odd OR a multiple of 3 are 1,3,5,6,7,9,11,12,13
or nine of them
so prob = 9/13
There is a formula which says
Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B)
= 4 + 7 - 2 = 9
notice that the 3 and 9 are in both sets, so if we just add up the count, we counted them twice, so we have to subtract one of the counts.
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