( 9x^2 - 4 )/( 3x^2 - 10x - 8 )
well the numerator is difference of two squares so factor
now I bet one of those is a factor of the denominator
(3x - 2)(x+4) no
so we really have
(3x+2)(3x-2) / (3x+2)(x-4)
(3x-2) / (x-4)
2 x^2 - 12 x + 5 = 0
I can not factor that, sure it is not 11 x?
If not a typo, use quadratic equation
x = [ -b +/- sqrt(b^2-4ac)] / 2a
g(x) = -4x^2 + 16x - 15
g is - for bi + or - x so upside down (sheds water)
Find the vertex.
4 x^2 - 16 x + 15 = -g
x^2 - 4 x = (-g-15)/4
x^2 - 4 x + 4 = -g/4 - 15/4 + 16/4
(x-2)^2 = (1/4) (-g +1)
AT VERTEX x = 2, g = +1
so max at (2,1)
y-9 = -2(x+3)^2
pretty much the same as the last one
same both sides of x = -3 so that is the vertical axis of symmetry
vertex at (-3,9)
when x gets big, y gets small, so sheds water
when y = 0
9/2 = (x+3)^2
x + 3 = +/- 3 /sqrt 2
x = -3 +/- 3/sqrt 2 is where he zeros are
Just brute force think your way through these problems !!!
OMG you are FREAKIN AWESOME for helping me out with these problems!!!!!! With your thorough explanations it all came back to me I thank you SOOOOOO MUCH!!!!!!
6x^4-15x^3+10x^2-10x+4 divided by 3x^2+2
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