complete and balance the following decompition equations
CaCO (heated) -->
3
please tell me how to do this and what exactly is suppose to be going through my head while doing this. I can balance these equations with no problem I just have no idea what to do...
Caronates when heated give off carbon dioxide and the metal oxide.
so wat do i do?
so you write the formula for calcium oxide (CaO) and carbon dioxide (CO2).
CaCO3 ==> CaO + CO2
What's going on? You need to recognize that carbonates, when heated, give off the metal oxide and CO2, write those products, then balance the equation.
To complete and balance a decomposition equation like the one you provided (CaCO3 -> CaO + CO2), you need to understand the reaction and the principles of balancing equations. Here's a step-by-step guide on how to approach this:
1. Understand the reaction: The given equation represents the decomposition of calcium carbonate (CaCO3) when heated. It breaks down into calcium oxide (CaO) and carbon dioxide (CO2) gas.
2. Identify the elements: Determine the elements present on both sides of the equation. In this case, we have calcium (Ca), carbon (C), and oxygen (O).
3. Balance the equation: Start by balancing the more complex molecules or the ones with the most elements. In this equation, CaCO3 already has one calcium, one carbon, and three oxygen atoms, so we'll balance CaO and CO2.
4. Balance CaO: Since we need one calcium atom on both sides, CaO already has one calcium atom, so it doesn't need any additional balancing.
5. Balance CO2: On the right side, CO2 already has one carbon atom and two oxygen atoms. To balance the equation, we need to have the same number of carbon and oxygen atoms on the left side. However, since there is only one carbon atom in CaCO3, it means that we will need one CO2 molecule to balance it. So, the final balanced equation is:
CaCO3 --> CaO + CO2
To summarize, when balancing the equation, you need to ensure that the number of atoms for each element is the same on both sides. The key is to start with the more complex molecules and work your way through, making adjustments until the equation is balanced.