a)If you roll a putty ball around inside of a bowl, it soon comes to a rest in the center. A steel ball will orbit quite a few times before coming to rest in the center of the bowl. What would be the ideal motion of the ball in the bowl? (no friction)

b) A car can accelerate by 3m/sec^2. What is its accleration if it is twoin another car like itself?

c)A skate boarder weighing 80lbs rides a 6lb skateboard down a 12 degree(from the horizontal) hill at a constant velocity. what is the force of friction acting on the board?

thank you for your time, i really appreciate it:) please help!!!

No friction? it loses no speed. It must travel in like an orbit forever.

If mass is doubled and the pulling force is the same...
F=Ma

The force down the hill is (86)sinTheta
if it is at constant speed, the friction must be equal and opposite.

thanks sooo much:)

a) The ideal motion of the ball in the bowl would be circular motion. This can be explained by the concept of centripetal force. When the ball is rolling around inside the bowl, the walls of the bowl exert an inward force towards the center of the bowl, which acts as the centripetal force. In the case of the putty ball, it quickly comes to rest in the center because there is little resistance or energy loss in the putty. However, the steel ball has more inertia and continues to orbit multiple times before coming to rest in the center due to its greater momentum.

b) To find the acceleration when the car is towing another car like itself, we can use the principle of inertia. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

Given that the car can accelerate by 3 m/sec^2, and assuming that the mass of the original car and the additional car are the same, we can expect the acceleration to be halved when the car is towing another car like itself. This is because the combination of the two cars has double the mass but the same net force, resulting in a reduction in acceleration.

Therefore, the acceleration in this scenario would be 1.5 m/sec^2.

c) To calculate the force of friction acting on the skateboard, we can use the equation:

Force of friction = coefficient of friction * normal force

The normal force is the force exerted by the skateboarder's weight perpendicular to the hill. We can calculate it using the equation:

Normal force = weight * cos(angle)

Weight of the skateboarder = 80 lbs = 80 * 9.8 N (converting to Newtons)

Weight of the skateboard = 6 lbs = 6 * 9.8 N (converting to Newtons)

Using the given angle of 12 degrees, we can calculate:

Normal force = (80 * 9.8 * cos(12)) + (6 * 9.8 * cos(12))

Next, we need to determine the coefficient of friction, which depends on the surface. Assuming it is not given, let's assume a typical value, such as 0.5.

Finally, we can calculate the force of friction:

Force of friction = 0.5 * (Normal force calculated above)

Please note that these calculations are approximate, and actual values may vary depending on the specific conditions and assumptions made.