sounds really confusing, sorry but i can't help you! i think this is too much for someone to explain online.
look at your triangle and find BC.
Mark the middle of that line, or the midpoint.
Join that point to point A with a line.
This line is called the median.
In any triangle there are three such medians, one from each vertex
We have just "connected vertex A to the midpoint of the opposite side BC", and called it the "median"
Now let's do this algebraically
the midpoint between any two given points is found by adding the x's, then dividing by 2,
and adding the y's , then dividing by 2
so the midpoint of BC is ((-3+1)/2,(-5+1)/2)
or (-1,-2), let's call it point D
in a) you are asked to find the equation of that line AD
slope AD = (-2-9)/(-1-5) = 11/6
so the line AD is y = (11/6)x + b
sub in the point (5,9), it lies on the line
9 = (11/6)(5) + b
multiply each side by 6
54= 55 + 6b
b = -1/6
so the median AD has equation y = (11/6)x - 1/6
now repeat the same steps for b)
for c) solve the two equations.
in d), I think you have a typo, probably meant to say "median C to the midpoint of line segment AB"
WOWOWOWOW REINY YOU ARE A GENIUS!!!!! ARE YOU A MATHEMATICIAN?? HOW DO YOU KNOW ALL THIS STUFF?? YOU ROCK GIRL:)
You're being so helpful, thank you! Just wondering, my triangle turned out to be very skinny. It's supposed to be this way, right?
And for part d, that is how my teacher typed it, but in the other day's homework he also did a typo.
Thank you so much! You were actually MUCH more help than my teacher. My teacher just stuck the homework in front of our faces and expected us to understand it.
how do i set up three proportions with measurements of 3x3x3 that show the side splitter theorem or similar triangles
What is the midpoint of the line segment that connects the points (1, 2) and (6, 7)?
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