Posted by Lana on Tuesday, December 16, 2008 at 9:39pm.
you are simply asked to find
(-50) + (-49) + ... + (-2) + (-1)
there are 50 of these, so n=50
the first term is -50, so a=-50
the common difference is 1, so d=1
S50 = 50/2(-50 + (-1) = -1275
I was using S(n) = n/2(first + last)
You could have used
S(n) = n/2[2a + (n-1)d]
= 25[-100 + 49]
= -1275
notice if you had added up the first 50 positive integers you would get +1275
oh! a = -50?!
for some reason I thought it was 1, but it makes much more sense now. Okay, yeah, I see what you mean. :) Thank you so very much for helping me! :D
Related Questions
math - the sum of 3 consecutive integers is the same value as twice the greatest...
college math - I do not understand a problem from a text book or how to solve ...
Math - When you solve questions like "The sum of 3 consecutive integers is ...
Algebra - Cant figure out what to do (equations) 1)Find three consecutive even ...
algebra - Find four consecutive odd integers so that five times the sum of the ...
math - i dont get this question consecutive integers are integers that differ by...
math-calculus - write the following absolute value functions as piecewise ...
math-calculus - write the following absolute value functions as piecewise ...
math - The sum of the reciprocals of two consecutive even integers is 11/60. ...
Precalculus - Find the sum of the first 50 terms of the sequence 2,4,6,8...
For Further Reading