Posted by **s** on Tuesday, December 16, 2008 at 7:17pm.

There is a square whose vertices lie on a unit circle. Point P lies on the terminal arm of an angle in standard position, P(0.3420, 0.9397)

how do you find the degrees of P?

- math -
**Reiny**, Tuesday, December 16, 2008 at 7:51pm
since it is a unit circle, that is the radius is 1, then P can be written as (cosß,sinß)

then cosß = .3420

then angle ß = 70º

notice you would get the same if you took

sin ß = .9397

ß = 70º and notice that

.3420^2 + .9397^2 = 1

- math -
**s**, Tuesday, December 16, 2008 at 7:54pm
thanks

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