There is a square whose vertices lie on a unit circle. Point P lies on the terminal arm of an angle in standard position, P(0.3420, 0.9397)

how do you find the degrees of P?

since it is a unit circle, that is the radius is 1, then P can be written as (cosß,sinß)

then cosß = .3420
then angle ß = 70º

notice you would get the same if you took
sin ß = .9397
ß = 70º and notice that

.3420^2 + .9397^2 = 1

thanks

To find the degrees of point P, you can use the inverse trigonometric functions (arcsin, arccos, arctan). In this case, you can use the arctan function to find the angle in radians, and then convert it to degrees.

1. Start by finding the angle in radians using the arctan function:
tan(theta) = y / x
theta = arctan(y / x)

In this case, y = 0.9397 and x = 0.3420, so:
theta = arctan(0.9397 / 0.3420)

2. Use a calculator to evaluate the arctan function:
theta ≈ 1.2291 radians

3. Finally, convert the angle from radians to degrees by multiplying by 180/pi:
degrees = 1.2291 * (180 / pi)

degrees ≈ 70.5314 degrees

Therefore, the angle of point P is approximately 70.5314 degrees.