Posted by s on Tuesday, December 16, 2008 at 7:17pm.
There is a square whose vertices lie on a unit circle. Point P lies on the terminal arm of an angle in standard position, P(0.3420, 0.9397)
how do you find the degrees of P?

math  Reiny, Tuesday, December 16, 2008 at 7:51pm
since it is a unit circle, that is the radius is 1, then P can be written as (cosß,sinß)
then cosß = .3420
then angle ß = 70º
notice you would get the same if you took
sin ß = .9397
ß = 70º and notice that
.3420^2 + .9397^2 = 1

math  s, Tuesday, December 16, 2008 at 7:54pm
thanks
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