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There is a square whose vertices lie on a unit circle. Point P lies on the terminal arm of an angle in standard position, P(0.3420, 0.9397)

how do you find the degrees of P?

  • math -

    since it is a unit circle, that is the radius is 1, then P can be written as (cosß,sinß)
    then cosß = .3420
    then angle ß = 70º

    notice you would get the same if you took
    sin ß = .9397
    ß = 70º and notice that

    .3420^2 + .9397^2 = 1

  • math -


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