Thursday
April 24, 2014

Homework Help: physics

Posted by Michelle on Tuesday, December 16, 2008 at 7:12pm.

Assuming Earth behaves as a perfect sphere with a radius of 6380 km, the standard gravitational acceleration,g, at sea level has a value of 9.80 m/s^2.
a.) As Earth rotates on its axis, objects at the equator experience a slightly different value of g due to additional centripetal acceleration. Calculate this adjusted value for g.
b.) Is this difference due to centripetal forces present at the poles? If g is dependent upon the position on the surface of Earth, why do we use the standard value of 9.80 m/s^2 in our calculations? Explain.
c.) Whats the value of g on board a space shuttle in a stable orbit at a height of 350 km above the equator? Hint: You don't need to know the mass of the space shuttle.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Physics help please - The space shuttle orbits at a distance of 335 km above the...
physics - A satellite moves in a circular orbit around the Earth at a speed of 5...
maths - body of weight is inversely propotional to square of its distance from ...
physics - How high does a rocket have to go above the Earth’s surface so that ...
Physics - A satellite moves in a circular orbit around the Earth at a speed of 5...
physics - A satellite moves in a circular orbit around the Earth at a speed of 5...
Physics - A satellite moves in a circular orbit around the Earth at a speed of 6...
Physics - A satellite moves in a circular orbit around the Earth at a speed of 5...
calculus - (1 pt) The acceleration due to gravity, g, is given by g = (G*M)/(r^2...
Physics - A satellite moves in a circular orbit around the Earth at a speed of ...

Search
Members