Posted by **Jamie Lynn** on Tuesday, December 16, 2008 at 5:38pm.

I have a question, if f(x)=x/2 and g(x)=3x+1 find:

a) (f+g)(x) i know you go x/2+3x+1.

but how do i solve that??

b) (f-g)(x) i know you go x/2-3x+1,

how do i solve?

c)(f*g)(x) how do i solve?

(f/g)(x) how do i solve??

f(g(x)) how do i solve??

thanks for your itmeee

- MATH PLEASEEEEE -
**Reiny**, Tuesday, December 16, 2008 at 5:51pm
for (f+g)(x) you would add up your two function expressions and simplify them

so (f+g)(x) = x/2 + 3x+1

= x/2 + (6x+2)/2 = (7x+2)/2

which is not what you have

suppose we use x=4

f(4)= 4/2 =2

g(4) = 13

so (f+g)(4) = 15

in my (f+g)(x) = (7x+2)/2

(f+g)(4) = (7(4)+2)/2 = 15

for (f-g)(x) you would subtract the two functions,

for (f*g)(x) you would multiply them, etc

test your answers in a similar way to the one I showed you

- MATH PLEASEEEEE -
**Jamie Lynn**, Tuesday, December 16, 2008 at 9:40pm
thanks so much:)

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