Posted by help on Tuesday, December 16, 2008 at 9:40am.
The key is finding the final position.
1) It goes 68*33/60 km east
2) it goes 68*30/60 40 deg E of N. Converting that to E and N displacements..
it goes 60(30/60)sin40 East
it goes 60(30/60)cos40 North
3) it goes E for 68(-59/60) Notice the negative sign which changes West to East.
Now add up the East components.
That gives you the net East.
Now add up the N components.
Now use Pythogerean theorum
displacement=sqrt(N^2 +E^2)
Magnitude avg velocity=displacement/timetotal.
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