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April 20, 2014

April 20, 2014

Posted by **Anonymous** on Tuesday, December 16, 2008 at 1:38am.

(m^5m)^-7/(m^-32n^8)

- math -
**Christiaan**, Tuesday, December 16, 2008 at 9:23am(m^5)*m = m^5*m^1 = m^(5+1) = m^6

(m^6)^-7 = m^(6*-7)=m^(-42)

m^(-42)/(m^(-32)*n^8) =

m^(-42-(-32))*n^(-8) =

m^(-10)*n^(-8) (=ANSWER)

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