Can someone show me the steps for solving this logarithm?

Question

Can someone show me the steps for solving this logarithm?

log₄x+log₄12=log<sub448

Thanks!

Answer 1

EDIT:

It's log₄x+log₄12=log₄48

Answer 2

recall log (AB) = log A + log B

so log₄x + log₄12 = log₄48 becomes
log₄(12x) = log₄48
then
12x = 48
x = 4

Answer 3

Of course! To solve the logarithmic equation log₄x + log₄12 = log₄48, we can use logarithmic properties to simplify the equation and then solve for x. Here are the steps:

Step 1: Use the logarithmic property log_b(xy) = log_bx + log_by to combine the two logarithms on the left side of the equation.

So, we have log₄(x * 12) = log₄48.

Step 2: Simplify the equation further by applying another logarithmic property log_bb^a = a.

In this case, we can simplify the equation to x * 12 = 48.

Step 3: Solve the resulting equation for x by isolating the variable. Divide both sides of the equation by 12:

x = 48 / 12.

Simplifying further, we get:

x = 4.

Therefore, the solution to the given logarithmic equation is x = 4.

I hope this explanation helps! Let me know if you have any further questions.

Can someone show me the steps for solving this logarithm?

EDIT:

recall log (AB) = log A + log B

Of course! To solve the logarithmic equation log4x + log412 = log448, we can use logarithmic properties to simplify the equation and then solve for x. Here are the steps:

Of course! To solve the logarithmic equation log₄x + log₄12 = log₄48, we can use logarithmic properties to simplify the equation and then solve for x. Here are the steps: