f(x)=1/x, g(x)=3X+1 find:
f(g(3)) how do i do thiss...
f(g(-2))
g.g, g.f, f.g, pleaseee help:)thanks for your timeee
you can first find g(3) = 10
then do f(1) = 1/10
so g(g(3)) = 1/10
you try the other one.
another way is to find f(g(x)) itself.
this would be practical if you had a whole bunch of question to find
f(g(x))
= 1/(3x+1)
notice the right side gives you 1/10 directly
my third line should have said
f(g(3)) = 1/10
for your last part,
e.g. gºg would mean g(g(x))
= 3(3x+1) + 1
= 9x+ 4
OHHH thanks reiniyyyy
To find f(g(3)), we need to start by finding g(3) first, and then plug that value into f(x).
1. Start by evaluating g(3) using the function g(x) = 3x + 1:
g(3) = 3(3) + 1
= 9 + 1
= 10
2. Now, plug the value of g(3) into the function f(x) = 1/x:
f(g(3)) = f(10)
= 1/10
Therefore, f(g(3)) evaluates to 1/10.
To find f(g(-2)), follow the same steps:
1. Find g(-2) using the function g(x) = 3x + 1:
g(-2) = 3(-2) + 1
= -6 + 1
= -5
2. Plug the value of g(-2) into the function f(x) = 1/x:
f(g(-2)) = f(-5)
= 1/(-5)
= -1/5
Therefore, f(g(-2)) evaluates to -1/5.
Regarding "g.g", "g.f", and "f.g", these indicate function compositions.
1. g.g means g(g(x)), which represents applying function g(x) twice:
g(g(x)) = g(3x + 1) = 3(3x + 1) + 1 = 9x + 3 + 1 = 9x + 4
2. g.f means g(f(x)), which involves applying function f(x) to the input of g(x):
g(f(x)) = g(1/x) = 3(1/x) + 1 = 3/x + 1
3. f.g means f(g(x)), which involves applying function g(x) to the input of f(x):
f(g(x)) = f(3x + 1) = 1/(3x + 1)
Remember, it's important to substitute the correct function values or expressions into the relevant functions to get the correct result.