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November 29, 2014

November 29, 2014

Posted by **Kennedy** on Monday, December 15, 2008 at 3:35pm.

f(x)=absoulte value of x-3.

f(x)=x^2-4x-8

f(x)=(x+1)(x+1)(x+1).

f(x)=4

f(x)=-'9x-1)^2+16

y=squareroot x.

i don't understand how i konw what the range, domain, and zeros are...please give some answers so i get it

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