Posted by **Lily** on Sunday, December 14, 2008 at 11:43pm.

ron and kathy are ticket-sellers at their class play, ron handling student tickets that sell for $3.00 each and kathy selling adult tickets for $6.50 each.

If their total income for 29 tickets was $125.50, how many did ron sell?

- elementary algebra -
**s**, Sunday, December 14, 2008 at 11:47pm
if its elementary algebra don't you draw some columns and guess and test?

otherwise, these are the equations:

x(3.00) + y(6.50) = $125.50

x+y = 29 tickets

- elementary algebra -
**DrBob222**, Sunday, December 14, 2008 at 11:51pm
Let R = # tickets sold by Ron.

and K = # tickets sold by Kathy.

=================================

R+K = 29

3R + 6.50K = 125.50

=======================

Two equations; two unknowns. Solve for R and K.

- elementary algebra -
**lisa**, Sunday, December 14, 2008 at 11:57pm
thank u guys!

- elementary algebra -
**shon**, Wednesday, April 1, 2009 at 10:08pm
5x-10=15

- elementary algebra -
**Teri**, Saturday, July 17, 2010 at 12:13am
-2+4(x-1)= -7-4x

- algebra1 -
**leslie**, Tuesday, May 1, 2012 at 6:01pm
your mama

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