March 26, 2017

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An Earth satellite moves in a circular orbit 775 km above the Earth's surface. The period of the motion is 100.1 min.
(a) What is the speed of the satellite?

(b) What is the magnitude of the centripetal acceleration of the satellite?

  • physics - ,

    R = Rearth + 775,000 meters

    speed = distance/time = 2 pi R/(100.1*60)

    Ac = speed^2/R

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