Posted by **Akitsuke** on Sunday, December 14, 2008 at 7:02am.

(0.2kg)(4190J/kg.degree Celsius)(T-70 degrees Celsius)+(0.1kg)(390J/kg.degree Celsius)(T-20 degrees Celsius)= 0.

how will I equate it to get the final Temperature? I don't understand how did they get the answer of T=67.8 degrees Celsius.

can someone explain it? Pls. I have an Exam tomorrow and I need to understand it. thanks

## Answer this Question

## Related Questions

- Physics - The water from two buckets is mixed together. One bucket contains 5kg ...
- Physics 20 - 1. How much heat energy is required to change 500 grams of water at...
- PHYSICS 102E - 1. How much ice at -10 degrees Celsius is required to cool a ...
- Math - Is this correct? The inside of your refrigerator might be set to a ...
- Algebra - In the metric system there are two official temperature scales: degree...
- Chemistry - Calculate the joules of energy involved when 11 grams of water at 10...
- Physics - Please Help! I am having difficulties grasping these concepts. Explain...
- Chemistry - A 100g sample of water at 90 degrees celsius is added to a 100g ...
- Chemistry - A 50g chuck of metal (c=0.506 j/g degrees celsius) is heated to 60 ...
- Chemistry - A 50g vhuck of metal (c=0.506 j/g degrees celsius) is heated to 60 ...

More Related Questions