Posted by **Akitsuke** on Sunday, December 14, 2008 at 7:02am.

(0.2kg)(4190J/kg.degree Celsius)(T-70 degrees Celsius)+(0.1kg)(390J/kg.degree Celsius)(T-20 degrees Celsius)= 0.

how will I equate it to get the final Temperature? I don't understand how did they get the answer of T=67.8 degrees Celsius.

can someone explain it? Pls. I have an Exam tomorrow and I need to understand it. thanks

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