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PHYSICS 102E

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(0.2kg)(4190J/kg.degree Celsius)(T-70 degrees Celsius)+(0.1kg)(390J/kg.degree Celsius)(T-20 degrees Celsius)= 0.

how will I equate it to get the final Temperature? I don't understand how did they get the answer of T=67.8 degrees Celsius.

can someone explain it? Pls. I have an Exam tomorrow and I need to understand it. thanks

  • PHYSICS 102E -

    Just do the algebra to get the final T. Stick the units (degrees C) on later.
    838.2*(T-70)+ 39(T-20)=0
    (838.2+39) T = 58764 + 5800
    T = 64564/878.2 = 73 C

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