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January 30, 2015

January 30, 2015

Posted by **anjelica318** on Saturday, December 13, 2008 at 6:52pm.

1-sin^2B

1. ----------- = csc^2B-sec^2B

sin^2Bcos^B

2. cos(2a+a) = 4cos^3a-3cosa

- trigo -
**drwls**, Saturday, December 13, 2008 at 9:52pm1. What exponent goes between ^ and cos? If it is 2, I do not believe the identity is valid as written.

What IS valid is

1/sin^2 B - sin^2B/(sin^2B cos^2 B) =

csc^2 B - sec^2 B

or

[cos^2 B - sin^2 B]/[sin^2B cos^2B ] =

csc^2 B - sec^2 B

- trigo -
**Anonymous**, Sunday, December 14, 2008 at 1:35am1. (1-sin²B)/(sin²Bcos²B)= csc²B-sec²B

--that's really the given. please help.

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