Posted by Michael on Saturday, December 13, 2008 at 12:01am.
You could use a least-squares linear fit, quadratic fit, or exponential fit. I'd favor the later. An easy way to do it would be by doing a linear fit of the log of the population.
Year Pop Log Pop
1950 132 2.12
1960 187 2.27
1970 254 2.40
1980 346 2.54
1990 466 2.67
2000 657 2.82
Note that the log(base 10)of the population changes by an average of 0.14 per decade
That is easily extrapolated to:
2010 (912) 2.96
2013 1000 3.00
as a Geometric Sequence, r=1.4
GROWTH FORMULA
C=Co(1+(r/100))^n
C=population you want to find(1 million)
Co=initial population (132 thousands)
r=1.4 so r/100=0.014 ,n is No. years
Hence,
1,000=132(1.014)^n
1.014^n=1000/132
n= log(100/132)/log1.014
and then you ll find a value, let's say x
you add x+1950=and get the year
I think it's right..you can work it out and post whether it worked or not.
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