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September 2, 2014

September 2, 2014

Posted by **johnny** on Thursday, December 11, 2008 at 9:55pm.

- physics -
**drwls**, Thursday, December 11, 2008 at 10:21pmIf the time is doubled by the presence of friction, the acceleration is reduced by a factor 4. (That is because (1/2)a*t^2 remains the same). The friction is therefore 3/4 of the component of the weight down the plane. (That leaves a net accelerating force that is 1/4 of the weight component down the slide).

M g cos 44 * uk = (3/4) M g sin 44

Solve for uk, the kinetic friction coefficient.

uk = (3/4) tan 44

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