Posted by johnny on Thursday, December 11, 2008 at 9:54pm.
47 km/h = 13.056 m/s
Compute the acceleration(a)when the stopping distance is X meters:
V^2 = 170.44 m^2/s^2 = 2 a X
a = V^2/(2X) = 85.22/X
M g * us = M a when a is as high as possible without slipping
M's cancel. You know the static fricion coefficient us. Substitute for a and solve for X
87m
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