Posted by Susan on Thursday, December 11, 2008 at 5:06pm.
You know the initial vertical velocity (35sin35).
Vf at top max height is zero. Use
vf=vivertical-gt to to find the time to the top, then use
h=ho+vivert*t-1/2 g t^2 to find the max height.
For time of flight, hf=0
0=ho+vivert*t-gt solve for t
now, having the time of flight, the horizontal distance will be
distance=vihoriz*t
is the correct answer for max height 20.58, and the correct answer for the range 58.77?
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