Posted by **Confused** on Thursday, December 11, 2008 at 4:07pm.

COS[ARCSIN (SIN 3PI/4)]

=COS[ARCSIN (SQRT2/2)]

=COS [PI/4]

= SQRT2/2

## Answer this Question

## Related Questions

- calculus - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x...
- Calc. - Differentiate. y= (cos x)^x u= cos x du= -sin x dx ln y = ln(cos x)^x ln...
- math - Eliminate the parameter (What does that mean?) and write a rectangular ...
- Math(Please help) - 1)tan Q = -3/4 Find cosQ -3^2 + 4^2 = x^2 9+16 = sqrt 25 = 5...
- Math(Please help) - 2) Use the sum and difference identites sin[x + pi/4] + sin[...
- Trigonometry (Help and Check) - Evaluate (exact answers): a) sin^-1(cos30) Need ...
- Trigonometry - I need help with I just can't seem to get anywhere. this is as ...
- maths - Please can you help me with this question? Choose the option which is a ...
- trig - please help me with some questions I skipped on a review for our test ...
- pre-calc - Can someone check my work please? Convert each polar equation to a ...

More Related Questions