Posted by **Sandhya** on Thursday, December 11, 2008 at 4:19am.

There is a horizontal rod of length L and mass M. A point mass m is vertically above the rod at a vertical distance L/4 and horizontal distance L/3 from one end of the rod.Using The Riemann sum Integral,find the magnitude and direction of the gravitational force exerted on the point mass by the rod.

- Physics -
**drwls**, Thursday, December 11, 2008 at 11:08am
Write the expression for the vertical and horizontal components of the gravoty force. It will require an integration along the length of the rod.

The vertical force component is

G*m*(M/L)*dx*(L/4)/[(L/4)^2 + x^2]^3/2

integrate that from x=0 to x = L

The messy looking denominator is the cube of the distance between mass m and dx. You need a cube instead of a square becasue you need to include a cosine term for the vertical component. For the horizontal force, you will have a different integral beasue you need a sine term.

Doing this with Riemann sums is rather messay and I will leave that you you or another teacher

## Answer this Question

## Related Questions

- Math - There is a horizontal rod of length L and mass M. A point mass m is ...
- physics - a 51.0 kg uniform square sign, of edge L = 2.00 m, is hung from a ...
- physics - A uniform rod of mass M = 0.245kg and length L = 0.49m stands ...
- Physics - A 2.5 m rod of mass M= 4. kg is attached to a pivot .8m from the left ...
- Physics - A mass of 100g is attached to one end of a massless rod, 10cm in ...
- physics - A thin non-uniform rod of length L=2.00 m and mass M=9.00 kg is free ...
- physics - A uniform thin rod of length 0.55 m and mass 5.5 kg can rotate in a ...
- Physics - In the figure, a thin uniform rod of mass m = 3.05 kg and length L = 1...
- AP Physics - A uniform thin rod of length 0.3m and mass 3.5kg can rotate in a ...
- College Physics - A uniform rod of mass M = 437.0 g and length L = 37.1 cm ...

More Related Questions