1. how many grams are in 5.66 mol of CaC03 (3 is the subscript)?
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mass= 5.66 mol CaCO3 x mass/1 mol CaCO3
How do i finish this off?
2. find the number of moles in 508g of ethanol (C2H6O)? 2 and 6 are subscripts
You are missing what a mole is. Take a look at the example problems here..
http://dbhs.wvusd.k12.ca.us/webdocs/Mole/Moles-to-Grams.html
To finish off the first question, we need to multiply the given mole quantity by the molar mass of CaCO3.
First, we'll find the molar mass of CaCO3 by adding up the atomic masses of each element present in the compound. The atomic masses are found on the periodic table.
The atomic mass of Ca (calcium) = 40.08 g/mol
The atomic mass of C (carbon) = 12.01 g/mol
The atomic mass of O (oxygen) = 16.00 g/mol
Next, we calculate the molar mass of CaCO3:
Molar mass of CaCO3 = (atomic mass of Ca) + (atomic mass of C) + (3 x atomic mass of O)
= (40.08 g/mol) + (12.01 g/mol) + (3 x 16.00 g/mol)
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
Now we can use the molar mass to calculate the mass in grams of 5.66 mol of CaCO3:
Mass = 5.66 mol CaCO3 x (100.09 g CaCO3 / 1 mol CaCO3)
= 566.034 g
Therefore, there are approximately 566.034 grams in 5.66 mol of CaCO3.
Moving on to the second question:
To find the number of moles in 508 grams of ethanol (C2H6O), we need to use the molar mass of ethanol.
The atomic mass of C (carbon) = 12.01 g/mol
The atomic mass of H (hydrogen) = 1.008 g/mol
The atomic mass of O (oxygen) = 16.00 g/mol
Now we calculate the molar mass of ethanol (C2H6O):
Molar mass of ethanol = (2 x atomic mass of C) + (6 x atomic mass of H) + (atomic mass of O)
= (2 x 12.01 g/mol) + (6 x 1.008 g/mol) + (16.00 g/mol)
= 24.02 g/mol + 6.048 g/mol + 16.00 g/mol
= 46.068 g/mol
To find the number of moles, divide the given mass of ethanol by its molar mass:
Number of moles = mass / molar mass
= 508 g / (46.068 g/mol)
≈ 11.02 mol
Therefore, there are approximately 11.02 moles in 508 grams of ethanol (C2H6O).