posted by Charlie on .
How large a pressure increase (in ATM) must be applied to water if it is to be compressed in volume by 1%? The bulk modulus of water is 2 ~ 10^9 N/m^2 and 1 ATM = 10^5 N/m^2
I think that it is
P = bulk modulus * 0.01
because 1/100 = 0.01, which is 1% of a volume.
B = ƒ¢P/ [(ƒ¢V/Vi)] < --- I found this equation.