Post a New Question


posted by .

A baseball is thrown, leaving the baseball player’s hand 6.0 ft about the ground and at a 45 degree angle with respect to the horizon. The initial speed is 80 ft/s. Find the maximum height attained, the length of time the ball stays in the air, and the horizontal distance where the ball hits the ground. (assume air resistance is negligible).

  • physics -

    YOu know the initial vertical component, and the initial horizontal component.

    final height=initialheight+vovertical*time-1/2 g time^2
    solve for time...this is time in the air.
    Now at max height, vvertical will be zero
    0=vovertical-g*time solve for time max height, then use that time in the h equation to determine height.

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question