Posted by **mary** on Wednesday, December 10, 2008 at 9:09pm.

A baseball is thrown, leaving the baseball player’s hand 6.0 ft about the ground and at a 45 degree angle with respect to the horizon. The initial speed is 80 ft/s. Find the maximum height attained, the length of time the ball stays in the air, and the horizontal distance where the ball hits the ground. (assume air resistance is negligible).

- physics -
**bobpursley**, Wednesday, December 10, 2008 at 9:15pm
YOu know the initial vertical component, and the initial horizontal component.

final height=initialheight+vovertical*time-1/2 g time^2

solve for time...this is time in the air.

Now at max height, vvertical will be zero

0=vovertical-g*time solve for time max height, then use that time in the h equation to determine height.

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