What is the resistance of a coffee maker that draws a current of 5.0A from 117V source?

What resistance would have to be added in parallel with the same coffee maker to increase the current to 15.0A?

Okay, so for the first part I got 23.4 Ohms since R=V/I, but I don't really understand the second question. Like, I understand what I'm suppossed to do, but I don't know how. I woul really appreciate some help with this. Thanks in davance. :)

Right on the first part.

Ok, you want a total resistance of 15ohm, you have one 23.4ohm.

1/15=1/R+1/23.4

solve for R

oh! So, the resistance has to equal the total current, right?

because, I think that's what was messing me up. I figured I'd need to use the formual you used, but I just wasn't sure how. Oh, this is really easy now that I get it, thank you so much for clearing this up! :D

oops. totally disregard my response. I read it quickly and thought the 15 was total resistance.

Total resistance will be 117/15 ohms

so

15/117=1/23.4 + 1/r

solve for r.

sorry, I am working in too much of a hurry.

PS. Thanks for catching it.

oh, haha, okay, I see. Well, thank you for correcting your answer. :)

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To answer the second question, you need to apply Ohm's Law again.

First, determine the resistance of the coffee maker using the formula R = V/I, as you did in the first part. Since the coffee maker draws a current of 5.0A from a 117V source, its resistance is indeed 23.4 Ohms.

Now, to find the resistance that needs to be added in parallel, let's call it R_parallel. When two resistors are connected in parallel, the total resistance (R_total) is given by the formula:

1/R_total = 1/R1 + 1/R2

Where R1 and R2 are the resistance values of the two resistors. In this case, R1 is the resistance of the coffee maker (23.4 Ohms), and R2 is the resistance that needs to be added.

Since the total current (I_total) is 15.0A, and the current through the coffee maker (I1) is 5.0A, we can use the formula for current in a parallel circuit:

1/I_total = 1/I1 + 1/I2

Where I2 is the current through the added resistance (R2).

Now, rearrange the two equations to solve for R2:

1/R_total = 1/R1 + 1/R2
1/R2 = 1/R_total - 1/R1
R2 = 1/(1/R_total - 1/R1)

Substituting the values, we get:

R2 = 1/(1/15 - 1/23.4)

Evaluating this expression will give you the resistance of the additional resistor needed to increase the current to 15.0A.