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August 29, 2014

August 29, 2014

Posted by **Juliette** on Wednesday, December 10, 2008 at 5:34pm.

1/thesqrootof 3. I follow the book's explanation, until it suggests dividing the sq. root of 3 by the square root of 3 times the square root of three. I do not understand how that reduces to the square root of three divided by three. What happened to the square root signs? How come this is not the square root of nine?

Thanks for your clarification!

- Algebra -
**bobpursley**, Wednesday, December 10, 2008 at 5:47pmrational denominator is a whole number denomiator.

example:

1/sqrt3 = sqrt3/(sqrt3*sqrt3)= sqrt3 /3

your last question; sqrt 9 is 3, a rational number.

One last example

1/(1-sqrt2) multiply numerator and denominor by the conjugate. Look that term up.

1*(1+sqrt2)/[(1-sqrt2)(1+sqrt2)]=

(1+sqrt2)/(1-2)= - (1+sqrt2)

I bet you see something like this very soon.

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