Posted by **sarah** on Tuesday, December 9, 2008 at 10:28pm.

The Hubble Space Telescope is orbiting Earth 600 km above Earth's surface. Earth's radius is about 6370 km. Use the Pythagorean Theorem to find he distance a from the telescope to Earth's horizon. Round your answer to the nearest ten kilometers.

- geometry -
**bobpursley**, Tuesday, December 9, 2008 at 10:33pm
Draw the figure. Note it is a right triangle, with hypotenuse of (Rearth+altitude), legs of Rearth, and of what you want to find.

- geometry -
**drwls**, Tuesday, December 9, 2008 at 10:36pm
There is a right trangle formed by points at the center of the Earth, the HST satellite and the point where a line from the satellite is tangent to the Earth. The hypotenuse (c) goes from the HST to the center of the Earth, and its length is 600 + 6370= 6970 km. The side that you want is

b^2 = c^2 - a^2, where a is the radius of the Earth.

- geometry -
**drwls**, Wednesday, December 10, 2008 at 1:00pm
b^2 = (6970)^2 - (6370)^2

= 8.004*10^6

b = 2829 km

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