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January 31, 2015

January 31, 2015

Posted by **Callie** on Tuesday, December 9, 2008 at 8:35pm.

- Math -
**drwls**, Tuesday, December 9, 2008 at 8:52pmAssume the corral will not be as long as the barn, and that is goes a distance x away from the barn. There are thus 2 sides with length x and one side with length 60-x. the total area enlosed is

A = x(60-2x)

Choose the value of x that maximizes A by completing the square.

A = -2x^2 + 60 x

= -2(x^2 -30x + 225) + 225

= ??? You finish it. That is a perfect square within the ()

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