Posted by Callie on Tuesday, December 9, 2008 at 8:35pm.
Assume the corral will not be as long as the barn, and that is goes a distance x away from the barn. There are thus 2 sides with length x and one side with length 60-x. the total area enlosed is
A = x(60-2x)
Choose the value of x that maximizes A by completing the square.
A = -2x^2 + 60 x
= -2(x^2 -30x + 225) + 225
= ??? You finish it. That is a perfect square within the ()
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