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Posted by on Sunday, December 7, 2008 at 11:21pm.

dP/dt = k(P-a)

dP/dt = kP-ka

dP/P = k-ka

is this right so far? was i supposed to distribute??? what do i need to do next???

  • Calculus - , Monday, December 8, 2008 at 7:02am

    The third equation does not follow from the second.

    This looks like a differential equation they want you to solve.

    What you need to do is integrate both sides of
    dP/(P-a) = k dt

    ln (P-a) = kt + constant

    C e^(kt) = P-a

    P = a + C e^(kt)

    C is an arbitrary constant that you will have to determine from an initial condition.

    check: dP/dt = k C e^(kt) = k (P-a)

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