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December 18, 2014

December 18, 2014

Posted by **Frustrated** on Sunday, December 7, 2008 at 5:20pm.

- math -
**Reiny**, Sunday, December 7, 2008 at 5:27pmI too am slightly frustrated, since I can't tell which order of operation to follow with your placement of brackets

is it sinx/cosx - [1/(sinx/cosx)] - 1 ??

if so, you have

tanx - 1/cotx - 1

= tanx - tanx - 1

= -1

- math -
**ATTN REINY**, Sunday, December 7, 2008 at 5:30pm(sinx/cosx-1)/ (cosx/sinx-1)

- math -
**Damon**, Sunday, December 7, 2008 at 6:03pm(tan x -1) / (1/tan x - 1)

(tan^2 x - tan x) / (1 - tan x)

tan x (tan x - 1)/(1 - tan x)

-tan x

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